|
|
|
|
|
|
|
|
|
|
|
|
$$$1 - u^{2}$$$的导数
您的输入
求$$$\frac{d}{du} \left(1 - u^{2}\right)$$$。
解答
和/差的导数等于导数的和/差：
$${\color{red}\left(\frac{d}{du} \left(1 - u^{2}\right)\right)} = {\color{red}\left(\frac{d}{du} \left(1\right) - \frac{d}{du} \left(u^{2}\right)\right)}$$常数的导数是$$$0$$$:
$${\color{red}\left(\frac{d}{du} \left(1\right)\right)} - \frac{d}{du} \left(u^{2}\right) = {\color{red}\left(0\right)} - \frac{d}{du} \left(u^{2}\right)$$应用幂次法则 $$$\frac{d}{du} \left(u^{n}\right) = n u^{n - 1}$$$，其中 $$$n = 2$$$:
$$- {\color{red}\left(\frac{d}{du} \left(u^{2}\right)\right)} = - {\color{red}\left(2 u\right)}$$因此，$$$\frac{d}{du} \left(1 - u^{2}\right) = - 2 u$$$。
答案
$$$\frac{d}{du} \left(1 - u^{2}\right) = - 2 u$$$A
Please try a new game Rotatly