Afgeleide van $$$e^{x} + \sin{\left(y z \right)}$$$ naar $$$y$$$
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Uw invoer
Bepaal $$$\frac{d}{dy} \left(e^{x} + \sin{\left(y z \right)}\right)$$$.
Oplossing
De afgeleide van een som/verschil is de som/het verschil van de afgeleiden:
$${\color{red}\left(\frac{d}{dy} \left(e^{x} + \sin{\left(y z \right)}\right)\right)} = {\color{red}\left(\frac{d}{dy} \left(e^{x}\right) + \frac{d}{dy} \left(\sin{\left(y z \right)}\right)\right)}$$De functie $$$\sin{\left(y z \right)}$$$ is de samenstelling $$$f{\left(g{\left(y \right)} \right)}$$$ van twee functies $$$f{\left(u \right)} = \sin{\left(u \right)}$$$ en $$$g{\left(y \right)} = y z$$$.
Pas de kettingregel $$$\frac{d}{dy} \left(f{\left(g{\left(y \right)} \right)}\right) = \frac{d}{du} \left(f{\left(u \right)}\right) \frac{d}{dy} \left(g{\left(y \right)}\right)$$$ toe:
$${\color{red}\left(\frac{d}{dy} \left(\sin{\left(y z \right)}\right)\right)} + \frac{d}{dy} \left(e^{x}\right) = {\color{red}\left(\frac{d}{du} \left(\sin{\left(u \right)}\right) \frac{d}{dy} \left(y z\right)\right)} + \frac{d}{dy} \left(e^{x}\right)$$De afgeleide van de sinus is $$$\frac{d}{du} \left(\sin{\left(u \right)}\right) = \cos{\left(u \right)}$$$:
$${\color{red}\left(\frac{d}{du} \left(\sin{\left(u \right)}\right)\right)} \frac{d}{dy} \left(y z\right) + \frac{d}{dy} \left(e^{x}\right) = {\color{red}\left(\cos{\left(u \right)}\right)} \frac{d}{dy} \left(y z\right) + \frac{d}{dy} \left(e^{x}\right)$$Keer terug naar de oorspronkelijke variabele:
$$\cos{\left({\color{red}\left(u\right)} \right)} \frac{d}{dy} \left(y z\right) + \frac{d}{dy} \left(e^{x}\right) = \cos{\left({\color{red}\left(y z\right)} \right)} \frac{d}{dy} \left(y z\right) + \frac{d}{dy} \left(e^{x}\right)$$Pas de regel van de constante factor $$$\frac{d}{dy} \left(c f{\left(y \right)}\right) = c \frac{d}{dy} \left(f{\left(y \right)}\right)$$$ toe met $$$c = z$$$ en $$$f{\left(y \right)} = y$$$:
$$\cos{\left(y z \right)} {\color{red}\left(\frac{d}{dy} \left(y z\right)\right)} + \frac{d}{dy} \left(e^{x}\right) = \cos{\left(y z \right)} {\color{red}\left(z \frac{d}{dy} \left(y\right)\right)} + \frac{d}{dy} \left(e^{x}\right)$$De afgeleide van een constante is $$$0$$$:
$$z \cos{\left(y z \right)} \frac{d}{dy} \left(y\right) + {\color{red}\left(\frac{d}{dy} \left(e^{x}\right)\right)} = z \cos{\left(y z \right)} \frac{d}{dy} \left(y\right) + {\color{red}\left(0\right)}$$Pas de machtsregel $$$\frac{d}{dy} \left(y^{n}\right) = n y^{n - 1}$$$ toe met $$$n = 1$$$, met andere woorden, $$$\frac{d}{dy} \left(y\right) = 1$$$:
$$z \cos{\left(y z \right)} {\color{red}\left(\frac{d}{dy} \left(y\right)\right)} = z \cos{\left(y z \right)} {\color{red}\left(1\right)}$$Dus, $$$\frac{d}{dy} \left(e^{x} + \sin{\left(y z \right)}\right) = z \cos{\left(y z \right)}$$$.
Antwoord
$$$\frac{d}{dy} \left(e^{x} + \sin{\left(y z \right)}\right) = z \cos{\left(y z \right)}$$$A