$$$x \sqrt{x - 1}$$$의 적분

$$$\int x \sqrt{x - 1}\, dx$$$을(를) 구하시오.

$$$u=x - 1$$$라 하자.

그러면 $$$du=\left(x - 1\right)^{\prime }dx = 1 dx$$$ (단계는 »에서 볼 수 있습니다), 그리고 $$$dx = du$$$임을 얻습니다.

따라서,

$${\color{red}{\int{x \sqrt{x - 1} d x}}} = {\color{red}{\int{\sqrt{u} \left(u + 1\right) d u}}}$$

Expand the expression:

$${\color{red}{\int{\sqrt{u} \left(u + 1\right) d u}}} = {\color{red}{\int{\left(u^{\frac{3}{2}} + \sqrt{u}\right)d u}}}$$

각 항별로 적분하십시오:

$${\color{red}{\int{\left(u^{\frac{3}{2}} + \sqrt{u}\right)d u}}} = {\color{red}{\left(\int{\sqrt{u} d u} + \int{u^{\frac{3}{2}} d u}\right)}}$$

멱법칙($$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$)을 $$$n=\frac{1}{2}$$$에 적용합니다:

$$\int{u^{\frac{3}{2}} d u} + {\color{red}{\int{\sqrt{u} d u}}}=\int{u^{\frac{3}{2}} d u} + {\color{red}{\int{u^{\frac{1}{2}} d u}}}=\int{u^{\frac{3}{2}} d u} + {\color{red}{\frac{u^{\frac{1}{2} + 1}}{\frac{1}{2} + 1}}}=\int{u^{\frac{3}{2}} d u} + {\color{red}{\left(\frac{2 u^{\frac{3}{2}}}{3}\right)}}$$

멱법칙($$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$)을 $$$n=\frac{3}{2}$$$에 적용합니다:

$$\frac{2 u^{\frac{3}{2}}}{3} + {\color{red}{\int{u^{\frac{3}{2}} d u}}}=\frac{2 u^{\frac{3}{2}}}{3} + {\color{red}{\frac{u^{1 + \frac{3}{2}}}{1 + \frac{3}{2}}}}=\frac{2 u^{\frac{3}{2}}}{3} + {\color{red}{\left(\frac{2 u^{\frac{5}{2}}}{5}\right)}}$$

다음 $$$u=x - 1$$$을 기억하라:

$$\frac{2 {\color{red}{u}}^{\frac{3}{2}}}{3} + \frac{2 {\color{red}{u}}^{\frac{5}{2}}}{5} = \frac{2 {\color{red}{\left(x - 1\right)}}^{\frac{3}{2}}}{3} + \frac{2 {\color{red}{\left(x - 1\right)}}^{\frac{5}{2}}}{5}$$

따라서,

$$\int{x \sqrt{x - 1} d x} = \frac{2 \left(x - 1\right)^{\frac{5}{2}}}{5} + \frac{2 \left(x - 1\right)^{\frac{3}{2}}}{3}$$

간단히 하시오:

$$\int{x \sqrt{x - 1} d x} = \frac{2 \left(x - 1\right)^{\frac{3}{2}} \left(3 x + 2\right)}{15}$$

적분 상수를 추가하세요:

$$\int{x \sqrt{x - 1} d x} = \frac{2 \left(x - 1\right)^{\frac{3}{2}} \left(3 x + 2\right)}{15}+C$$

$$$\int x \sqrt{x - 1}\, dx = \frac{2 \left(x - 1\right)^{\frac{3}{2}} \left(3 x + 2\right)}{15} + C$$$A