$$$\frac{1}{2 y}$$$의 적분

$$$\int \frac{1}{2 y}\, dy$$$을(를) 구하시오.

상수배 법칙 $$$\int c f{\left(y \right)}\, dy = c \int f{\left(y \right)}\, dy$$$을 $$$c=\frac{1}{2}$$$와 $$$f{\left(y \right)} = \frac{1}{y}$$$에 적용하세요:

$${\color{red}{\int{\frac{1}{2 y} d y}}} = {\color{red}{\left(\frac{\int{\frac{1}{y} d y}}{2}\right)}}$$

$$$\frac{1}{y}$$$의 적분은 $$$\int{\frac{1}{y} d y} = \ln{\left(\left|{y}\right| \right)}$$$:

$$\frac{{\color{red}{\int{\frac{1}{y} d y}}}}{2} = \frac{{\color{red}{\ln{\left(\left|{y}\right| \right)}}}}{2}$$

따라서,

$$\int{\frac{1}{2 y} d y} = \frac{\ln{\left(\left|{y}\right| \right)}}{2}$$

적분 상수를 추가하세요:

$$\int{\frac{1}{2 y} d y} = \frac{\ln{\left(\left|{y}\right| \right)}}{2}+C$$

$$$\int \frac{1}{2 y}\, dy = \frac{\ln\left(\left|{y}\right|\right)}{2} + C$$$A