정적분 및 가적분 계산기

이 계산기는 단계별 풀이를 보여 주면서 상한과 하한이 있는 정적분(진정적분 포함)을 계산하려고 시도합니다.

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Solution

Your input: calculate $$$\int_{1}^{2}\left( 4 x^{3} - x \right)dx$$$

First, calculate the corresponding indefinite integral: $$$\int{\left(4 x^{3} - x\right)d x}=x^{4} - \frac{x^{2}}{2}$$$ (for steps, see indefinite integral calculator)

According to the Fundamental Theorem of Calculus, $$$\int_a^b F(x) dx=f(b)-f(a)$$$, so just evaluate the integral at the endpoints, and that's the answer.

$$$\left(x^{4} - \frac{x^{2}}{2}\right)|_{\left(x=2\right)}=14$$$

$$$\left(x^{4} - \frac{x^{2}}{2}\right)|_{\left(x=1\right)}=\frac{1}{2}$$$

$$$\int_{1}^{2}\left( 4 x^{3} - x \right)dx=\left(x^{4} - \frac{x^{2}}{2}\right)|_{\left(x=2\right)}-\left(x^{4} - \frac{x^{2}}{2}\right)|_{\left(x=1\right)}=\frac{27}{2}$$$

Answer: $$$\int_{1}^{2}\left( 4 x^{3} - x \right)dx=\frac{27}{2}=13.5$$$

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정적분 및 가적분 계산기

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Solution