Integral dari $$$x^{2} \left(x^{3} - 5\right)^{7}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int x^{2} \left(x^{3} - 5\right)^{7}\, dx$$$.
Solusi
Misalkan $$$u=x^{3} - 5$$$.
Kemudian $$$du=\left(x^{3} - 5\right)^{\prime }dx = 3 x^{2} dx$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$x^{2} dx = \frac{du}{3}$$$.
Integral tersebut dapat ditulis ulang sebagai
$${\color{red}{\int{x^{2} \left(x^{3} - 5\right)^{7} d x}}} = {\color{red}{\int{\frac{u^{7}}{3} d u}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{3}$$$ dan $$$f{\left(u \right)} = u^{7}$$$:
$${\color{red}{\int{\frac{u^{7}}{3} d u}}} = {\color{red}{\left(\frac{\int{u^{7} d u}}{3}\right)}}$$
Terapkan aturan pangkat $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ dengan $$$n=7$$$:
$$\frac{{\color{red}{\int{u^{7} d u}}}}{3}=\frac{{\color{red}{\frac{u^{1 + 7}}{1 + 7}}}}{3}=\frac{{\color{red}{\left(\frac{u^{8}}{8}\right)}}}{3}$$
Ingat bahwa $$$u=x^{3} - 5$$$:
$$\frac{{\color{red}{u}}^{8}}{24} = \frac{{\color{red}{\left(x^{3} - 5\right)}}^{8}}{24}$$
Oleh karena itu,
$$\int{x^{2} \left(x^{3} - 5\right)^{7} d x} = \frac{\left(x^{3} - 5\right)^{8}}{24}$$
Tambahkan konstanta integrasi:
$$\int{x^{2} \left(x^{3} - 5\right)^{7} d x} = \frac{\left(x^{3} - 5\right)^{8}}{24}+C$$
Jawaban
$$$\int x^{2} \left(x^{3} - 5\right)^{7}\, dx = \frac{\left(x^{3} - 5\right)^{8}}{24} + C$$$A