Integral dari $$$\sin^{2}{\left(x_{0} \right)}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \sin^{2}{\left(x_{0} \right)}\, dx_{0}$$$.
Solusi
Terapkan rumus reduksi pangkat $$$\sin^{2}{\left(\alpha \right)} = \frac{1}{2} - \frac{\cos{\left(2 \alpha \right)}}{2}$$$ dengan $$$\alpha=x_{0}$$$:
$${\color{red}{\int{\sin^{2}{\left(x_{0} \right)} d x_{0}}}} = {\color{red}{\int{\left(\frac{1}{2} - \frac{\cos{\left(2 x_{0} \right)}}{2}\right)d x_{0}}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(x_{0} \right)}\, dx_{0} = c \int f{\left(x_{0} \right)}\, dx_{0}$$$ dengan $$$c=\frac{1}{2}$$$ dan $$$f{\left(x_{0} \right)} = 1 - \cos{\left(2 x_{0} \right)}$$$:
$${\color{red}{\int{\left(\frac{1}{2} - \frac{\cos{\left(2 x_{0} \right)}}{2}\right)d x_{0}}}} = {\color{red}{\left(\frac{\int{\left(1 - \cos{\left(2 x_{0} \right)}\right)d x_{0}}}{2}\right)}}$$
Integralkan suku demi suku:
$$\frac{{\color{red}{\int{\left(1 - \cos{\left(2 x_{0} \right)}\right)d x_{0}}}}}{2} = \frac{{\color{red}{\left(\int{1 d x_{0}} - \int{\cos{\left(2 x_{0} \right)} d x_{0}}\right)}}}{2}$$
Terapkan aturan konstanta $$$\int c\, dx_{0} = c x_{0}$$$ dengan $$$c=1$$$:
$$- \frac{\int{\cos{\left(2 x_{0} \right)} d x_{0}}}{2} + \frac{{\color{red}{\int{1 d x_{0}}}}}{2} = - \frac{\int{\cos{\left(2 x_{0} \right)} d x_{0}}}{2} + \frac{{\color{red}{x_{0}}}}{2}$$
Misalkan $$$u=2 x_{0}$$$.
Kemudian $$$du=\left(2 x_{0}\right)^{\prime }dx_{0} = 2 dx_{0}$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$dx_{0} = \frac{du}{2}$$$.
Dengan demikian,
$$\frac{x_{0}}{2} - \frac{{\color{red}{\int{\cos{\left(2 x_{0} \right)} d x_{0}}}}}{2} = \frac{x_{0}}{2} - \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{2} d u}}}}{2}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=\frac{1}{2}$$$ dan $$$f{\left(u \right)} = \cos{\left(u \right)}$$$:
$$\frac{x_{0}}{2} - \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{2} d u}}}}{2} = \frac{x_{0}}{2} - \frac{{\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{2}\right)}}}{2}$$
Integral dari kosinus adalah $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:
$$\frac{x_{0}}{2} - \frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{4} = \frac{x_{0}}{2} - \frac{{\color{red}{\sin{\left(u \right)}}}}{4}$$
Ingat bahwa $$$u=2 x_{0}$$$:
$$\frac{x_{0}}{2} - \frac{\sin{\left({\color{red}{u}} \right)}}{4} = \frac{x_{0}}{2} - \frac{\sin{\left({\color{red}{\left(2 x_{0}\right)}} \right)}}{4}$$
Oleh karena itu,
$$\int{\sin^{2}{\left(x_{0} \right)} d x_{0}} = \frac{x_{0}}{2} - \frac{\sin{\left(2 x_{0} \right)}}{4}$$
Tambahkan konstanta integrasi:
$$\int{\sin^{2}{\left(x_{0} \right)} d x_{0}} = \frac{x_{0}}{2} - \frac{\sin{\left(2 x_{0} \right)}}{4}+C$$
Jawaban
$$$\int \sin^{2}{\left(x_{0} \right)}\, dx_{0} = \left(\frac{x_{0}}{2} - \frac{\sin{\left(2 x_{0} \right)}}{4}\right) + C$$$A