Integral dari $$$6^{- 3 x}$$$

Temukan $$$\int 6^{- 3 x}\, dx$$$.

Masukan ditulis ulang: $$$\int{6^{- 3 x} d x}=\int{216^{- x} d x}$$$.

Misalkan $$$u=- x$$$.

Kemudian $$$du=\left(- x\right)^{\prime }dx = - dx$$$ (langkah-langkah dapat dilihat di »), dan kita memperoleh $$$dx = - du$$$.

Integralnya menjadi

$${\color{red}{\int{216^{- x} d x}}} = {\color{red}{\int{\left(- 216^{u}\right)d u}}}$$

Terapkan aturan pengali konstanta $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ dengan $$$c=-1$$$ dan $$$f{\left(u \right)} = 216^{u}$$$:

$${\color{red}{\int{\left(- 216^{u}\right)d u}}} = {\color{red}{\left(- \int{216^{u} d u}\right)}}$$

Apply the exponential rule $$$\int{a^{u} d u} = \frac{a^{u}}{\ln{\left(a \right)}}$$$ with $$$a=216$$$:

$$- {\color{red}{\int{216^{u} d u}}} = - {\color{red}{\frac{216^{u}}{\ln{\left(216 \right)}}}}$$

Ingat bahwa $$$u=- x$$$:

$$- \frac{216^{{\color{red}{u}}}}{\ln{\left(216 \right)}} = - \frac{216^{{\color{red}{\left(- x\right)}}}}{\ln{\left(216 \right)}}$$

Oleh karena itu,

$$\int{216^{- x} d x} = - \frac{216^{- x}}{\ln{\left(216 \right)}}$$

Sederhanakan:

$$\int{216^{- x} d x} = - \frac{216^{- x}}{3 \ln{\left(6 \right)}}$$

Tambahkan konstanta integrasi:

$$\int{216^{- x} d x} = - \frac{216^{- x}}{3 \ln{\left(6 \right)}}+C$$

$$$\int 6^{- 3 x}\, dx = - \frac{216^{- x}}{3 \ln\left(6\right)} + C$$$A