Määrättyjen ja epäoleellisten integraalien laskin
Laske määrättyjä ja epäoleellisia integraaleja askel askeleelta
Laskin yrittää laskea määrätyn (eli rajoilla varustetun) integraalin, mukaan lukien epäoleelliset tapaukset, ja näyttää välivaiheet.
Solution
Your input: calculate $$$\int_{-1}^{1}\left( \operatorname{acos}{\left(x \right)} \right)dx$$$
First, calculate the corresponding indefinite integral: $$$\int{\operatorname{acos}{\left(x \right)} d x}=x \operatorname{acos}{\left(x \right)} - \sqrt{1 - x^{2}}$$$ (for steps, see indefinite integral calculator)
According to the Fundamental Theorem of Calculus, $$$\int_a^b F(x) dx=f(b)-f(a)$$$, so just evaluate the integral at the endpoints, and that's the answer.
$$$\left(x \operatorname{acos}{\left(x \right)} - \sqrt{1 - x^{2}}\right)|_{\left(x=1\right)}=0$$$
$$$\left(x \operatorname{acos}{\left(x \right)} - \sqrt{1 - x^{2}}\right)|_{\left(x=-1\right)}=- \pi$$$
$$$\int_{-1}^{1}\left( \operatorname{acos}{\left(x \right)} \right)dx=\left(x \operatorname{acos}{\left(x \right)} - \sqrt{1 - x^{2}}\right)|_{\left(x=1\right)}-\left(x \operatorname{acos}{\left(x \right)} - \sqrt{1 - x^{2}}\right)|_{\left(x=-1\right)}=\pi$$$
Answer: $$$\int_{-1}^{1}\left( \operatorname{acos}{\left(x \right)} \right)dx=\pi\approx 3.14159265358979$$$