Integral of $$$e^{t^{2}}$$$

Find $$$\int e^{t^{2}}\, dt$$$.

This integral (Imaginary Error Function) does not have a closed form:

$${\color{red}{\int{e^{t^{2}} d t}}} = {\color{red}{\left(\frac{\sqrt{\pi} \operatorname{erfi}{\left(t \right)}}{2}\right)}}$$

Therefore,

$$\int{e^{t^{2}} d t} = \frac{\sqrt{\pi} \operatorname{erfi}{\left(t \right)}}{2}$$

Add the constant of integration:

$$\int{e^{t^{2}} d t} = \frac{\sqrt{\pi} \operatorname{erfi}{\left(t \right)}}{2}+C$$

$$$\int e^{t^{2}}\, dt = \frac{\sqrt{\pi} \operatorname{erfi}{\left(t \right)}}{2} + C$$$A