Integral of $$$- \frac{x^{2}}{y^{2}}$$$ with respect to $$$x$$$
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Your Input
Find $$$\int \left(- \frac{x^{2}}{y^{2}}\right)\, dx$$$.
Solution
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=- \frac{1}{y^{2}}$$$ and $$$f{\left(x \right)} = x^{2}$$$:
$${\color{red}{\int{\left(- \frac{x^{2}}{y^{2}}\right)d x}}} = {\color{red}{\left(- \frac{\int{x^{2} d x}}{y^{2}}\right)}}$$
Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=2$$$:
$$- \frac{{\color{red}{\int{x^{2} d x}}}}{y^{2}}=- \frac{{\color{red}{\frac{x^{1 + 2}}{1 + 2}}}}{y^{2}}=- \frac{{\color{red}{\left(\frac{x^{3}}{3}\right)}}}{y^{2}}$$
Therefore,
$$\int{\left(- \frac{x^{2}}{y^{2}}\right)d x} = - \frac{x^{3}}{3 y^{2}}$$
Add the constant of integration:
$$\int{\left(- \frac{x^{2}}{y^{2}}\right)d x} = - \frac{x^{3}}{3 y^{2}}+C$$
Answer
$$$\int \left(- \frac{x^{2}}{y^{2}}\right)\, dx = - \frac{x^{3}}{3 y^{2}} + C$$$A