Integral of $$$\frac{e^{- t^{2} x^{2}}}{t^{2}}$$$ with respect to $$$x$$$
Related calculator: Definite and Improper Integral Calculator
Your Input
Find $$$\int \frac{e^{- t^{2} x^{2}}}{t^{2}}\, dx$$$.
Solution
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{1}{t^{2}}$$$ and $$$f{\left(x \right)} = e^{- t^{2} x^{2}}$$$:
$${\color{red}{\int{\frac{e^{- t^{2} x^{2}}}{t^{2}} d x}}} = {\color{red}{\frac{\int{e^{- t^{2} x^{2}} d x}}{t^{2}}}}$$
Let $$$u=x \left|{t}\right|$$$.
Then $$$du=\left(x \left|{t}\right|\right)^{\prime }dx = \left|{t}\right| dx$$$ (steps can be seen »), and we have that $$$dx = \frac{du}{\left|{t}\right|}$$$.
The integral becomes
$$\frac{{\color{red}{\int{e^{- t^{2} x^{2}} d x}}}}{t^{2}} = \frac{{\color{red}{\int{\frac{e^{- u^{2}}}{\left|{t}\right|} d u}}}}{t^{2}}$$
Apply the constant multiple rule $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ with $$$c=\frac{1}{\left|{t}\right|}$$$ and $$$f{\left(u \right)} = e^{- u^{2}}$$$:
$$\frac{{\color{red}{\int{\frac{e^{- u^{2}}}{\left|{t}\right|} d u}}}}{t^{2}} = \frac{{\color{red}{\frac{\int{e^{- u^{2}} d u}}{\left|{t}\right|}}}}{t^{2}}$$
This integral (Error Function) does not have a closed form:
$$\frac{{\color{red}{\int{e^{- u^{2}} d u}}}}{t^{2} \left|{t}\right|} = \frac{{\color{red}{\left(\frac{\sqrt{\pi} \operatorname{erf}{\left(u \right)}}{2}\right)}}}{t^{2} \left|{t}\right|}$$
Recall that $$$u=x \left|{t}\right|$$$:
$$\frac{\sqrt{\pi} \operatorname{erf}{\left({\color{red}{u}} \right)}}{2 t^{2} \left|{t}\right|} = \frac{\sqrt{\pi} \operatorname{erf}{\left({\color{red}{x \left|{t}\right|}} \right)}}{2 t^{2} \left|{t}\right|}$$
Therefore,
$$\int{\frac{e^{- t^{2} x^{2}}}{t^{2}} d x} = \frac{\sqrt{\pi} \operatorname{erf}{\left(x \left|{t}\right| \right)}}{2 t^{2} \left|{t}\right|}$$
Add the constant of integration:
$$\int{\frac{e^{- t^{2} x^{2}}}{t^{2}} d x} = \frac{\sqrt{\pi} \operatorname{erf}{\left(x \left|{t}\right| \right)}}{2 t^{2} \left|{t}\right|}+C$$
Answer
$$$\int \frac{e^{- t^{2} x^{2}}}{t^{2}}\, dx = \frac{\sqrt{\pi} \operatorname{erf}{\left(x \left|{t}\right| \right)}}{2 t^{2} \left|{t}\right|} + C$$$A