Integral of $$$\frac{\pi x \sin{\left(7 \right)}}{20}$$$
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Your Input
Find $$$\int \frac{\pi x \sin{\left(7 \right)}}{20}\, dx$$$.
Solution
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=\frac{\pi \sin{\left(7 \right)}}{20}$$$ and $$$f{\left(x \right)} = x$$$:
$${\color{red}{\int{\frac{\pi x \sin{\left(7 \right)}}{20} d x}}} = {\color{red}{\left(\frac{\pi \sin{\left(7 \right)} \int{x d x}}{20}\right)}}$$
Apply the power rule $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ with $$$n=1$$$:
$$\frac{\pi \sin{\left(7 \right)} {\color{red}{\int{x d x}}}}{20}=\frac{\pi \sin{\left(7 \right)} {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}}{20}=\frac{\pi \sin{\left(7 \right)} {\color{red}{\left(\frac{x^{2}}{2}\right)}}}{20}$$
Therefore,
$$\int{\frac{\pi x \sin{\left(7 \right)}}{20} d x} = \frac{\pi x^{2} \sin{\left(7 \right)}}{40}$$
Add the constant of integration:
$$\int{\frac{\pi x \sin{\left(7 \right)}}{20} d x} = \frac{\pi x^{2} \sin{\left(7 \right)}}{40}+C$$
Answer
$$$\int \frac{\pi x \sin{\left(7 \right)}}{20}\, dx = \frac{\pi x^{2} \sin{\left(7 \right)}}{40} + C$$$A