$$$\frac{\sqrt{2} \sin{\left(2 x \right)}}{\cos^{3}{\left(x \right)}}$$$ 的積分

此計算器將求出 $$$\frac{\sqrt{2} \sin{\left(2 x \right)}}{\cos^{3}{\left(x \right)}}$$$ 的不定積分(原函數),並顯示步驟。

相關計算器: 定積分與廣義積分計算器

請不要使用任何微分符號,例如 $$$dx$$$$$$dy$$$ 等。
留空以自動偵測。

如果計算器未能計算某些內容,或您發現了錯誤,或您有任何建議/回饋,請聯絡我們

您的輸入

$$$\int \frac{\sqrt{2} \sin{\left(2 x \right)}}{\cos^{3}{\left(x \right)}}\, dx$$$

解答

重寫被積函數:

$${\color{red}{\int{\frac{\sqrt{2} \sin{\left(2 x \right)}}{\cos^{3}{\left(x \right)}} d x}}} = {\color{red}{\int{\frac{2 \sqrt{2} \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x}}}$$

套用常數倍法則 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$,使用 $$$c=2 \sqrt{2}$$$$$$f{\left(x \right)} = \frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}$$$

$${\color{red}{\int{\frac{2 \sqrt{2} \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x}}} = {\color{red}{\left(2 \sqrt{2} \int{\frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x}\right)}}$$

$$$u=\cos{\left(x \right)}$$$

$$$du=\left(\cos{\left(x \right)}\right)^{\prime }dx = - \sin{\left(x \right)} dx$$$ (步驟見»),並可得 $$$\sin{\left(x \right)} dx = - du$$$

該積分可改寫為

$$2 \sqrt{2} {\color{red}{\int{\frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x}}} = 2 \sqrt{2} {\color{red}{\int{\left(- \frac{1}{u^{2}}\right)d u}}}$$

套用常數倍法則 $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$,使用 $$$c=-1$$$$$$f{\left(u \right)} = \frac{1}{u^{2}}$$$

$$2 \sqrt{2} {\color{red}{\int{\left(- \frac{1}{u^{2}}\right)d u}}} = 2 \sqrt{2} {\color{red}{\left(- \int{\frac{1}{u^{2}} d u}\right)}}$$

套用冪次法則 $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$,以 $$$n=-2$$$

$$- 2 \sqrt{2} {\color{red}{\int{\frac{1}{u^{2}} d u}}}=- 2 \sqrt{2} {\color{red}{\int{u^{-2} d u}}}=- 2 \sqrt{2} {\color{red}{\frac{u^{-2 + 1}}{-2 + 1}}}=- 2 \sqrt{2} {\color{red}{\left(- u^{-1}\right)}}=- 2 \sqrt{2} {\color{red}{\left(- \frac{1}{u}\right)}}$$

回顧一下 $$$u=\cos{\left(x \right)}$$$

$$2 \sqrt{2} {\color{red}{u}}^{-1} = 2 \sqrt{2} {\color{red}{\cos{\left(x \right)}}}^{-1}$$

因此,

$$\int{\frac{\sqrt{2} \sin{\left(2 x \right)}}{\cos^{3}{\left(x \right)}} d x} = \frac{2 \sqrt{2}}{\cos{\left(x \right)}}$$

加上積分常數:

$$\int{\frac{\sqrt{2} \sin{\left(2 x \right)}}{\cos^{3}{\left(x \right)}} d x} = \frac{2 \sqrt{2}}{\cos{\left(x \right)}}+C$$

答案

$$$\int \frac{\sqrt{2} \sin{\left(2 x \right)}}{\cos^{3}{\left(x \right)}}\, dx = \frac{2 \sqrt{2}}{\cos{\left(x \right)}} + C$$$A


Please try a new game Rotatly