$$$\cos{\left(8 x \right)}$$$ 的積分
您的輸入
求$$$\int \cos{\left(8 x \right)}\, dx$$$。
解答
令 $$$u=8 x$$$。
則 $$$du=\left(8 x\right)^{\prime }dx = 8 dx$$$ (步驟見»),並可得 $$$dx = \frac{du}{8}$$$。
該積分變為
$${\color{red}{\int{\cos{\left(8 x \right)} d x}}} = {\color{red}{\int{\frac{\cos{\left(u \right)}}{8} d u}}}$$
套用常數倍法則 $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$,使用 $$$c=\frac{1}{8}$$$ 與 $$$f{\left(u \right)} = \cos{\left(u \right)}$$$:
$${\color{red}{\int{\frac{\cos{\left(u \right)}}{8} d u}}} = {\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{8}\right)}}$$
餘弦函數的積分為 $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:
$$\frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{8} = \frac{{\color{red}{\sin{\left(u \right)}}}}{8}$$
回顧一下 $$$u=8 x$$$:
$$\frac{\sin{\left({\color{red}{u}} \right)}}{8} = \frac{\sin{\left({\color{red}{\left(8 x\right)}} \right)}}{8}$$
因此,
$$\int{\cos{\left(8 x \right)} d x} = \frac{\sin{\left(8 x \right)}}{8}$$
加上積分常數:
$$\int{\cos{\left(8 x \right)} d x} = \frac{\sin{\left(8 x \right)}}{8}+C$$
答案
$$$\int \cos{\left(8 x \right)}\, dx = \frac{\sin{\left(8 x \right)}}{8} + C$$$A