$$$u + 1$$$ 的導數
您的輸入
求$$$\frac{d}{du} \left(u + 1\right)$$$。
解答
和/差的導數等於導數的和/差:
$${\color{red}\left(\frac{d}{du} \left(u + 1\right)\right)} = {\color{red}\left(\frac{d}{du} \left(u\right) + \frac{d}{du} \left(1\right)\right)}$$套用冪次法則 $$$\frac{d}{du} \left(u^{n}\right) = n u^{n - 1}$$$,取 $$$n = 1$$$,也就是 $$$\frac{d}{du} \left(u\right) = 1$$$:
$${\color{red}\left(\frac{d}{du} \left(u\right)\right)} + \frac{d}{du} \left(1\right) = {\color{red}\left(1\right)} + \frac{d}{du} \left(1\right)$$常數的導數為$$$0$$$:
$${\color{red}\left(\frac{d}{du} \left(1\right)\right)} + 1 = {\color{red}\left(0\right)} + 1$$因此,$$$\frac{d}{du} \left(u + 1\right) = 1$$$。
答案
$$$\frac{d}{du} \left(u + 1\right) = 1$$$A
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