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$$$t - \sqrt{2}$$$ 的導數
您的輸入
求$$$\frac{d}{dt} \left(t - \sqrt{2}\right)$$$。
解答
和/差的導數等於導數的和/差：
$${\color{red}\left(\frac{d}{dt} \left(t - \sqrt{2}\right)\right)} = {\color{red}\left(\frac{d}{dt} \left(t\right) - \frac{d}{dt} \left(\sqrt{2}\right)\right)}$$常數的導數為$$$0$$$：
$$- {\color{red}\left(\frac{d}{dt} \left(\sqrt{2}\right)\right)} + \frac{d}{dt} \left(t\right) = - {\color{red}\left(0\right)} + \frac{d}{dt} \left(t\right)$$套用冪次法則 $$$\frac{d}{dt} \left(t^{n}\right) = n t^{n - 1}$$$，取 $$$n = 1$$$，也就是 $$$\frac{d}{dt} \left(t\right) = 1$$$：
$${\color{red}\left(\frac{d}{dt} \left(t\right)\right)} = {\color{red}\left(1\right)}$$因此，$$$\frac{d}{dt} \left(t - \sqrt{2}\right) = 1$$$。
答案
$$$\frac{d}{dt} \left(t - \sqrt{2}\right) = 1$$$A
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