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$$$i k n t t_{1}$$$ 對 $$$t$$$ 的導數
您的輸入
求$$$\frac{d}{dt} \left(i k n t t_{1}\right)$$$。
解答
套用常數倍法則 $$$\frac{d}{dt} \left(c f{\left(t \right)}\right) = c \frac{d}{dt} \left(f{\left(t \right)}\right)$$$，使用 $$$c = i k n t_{1}$$$ 與 $$$f{\left(t \right)} = t$$$：
$${\color{red}\left(\frac{d}{dt} \left(i k n t t_{1}\right)\right)} = {\color{red}\left(i k n t_{1} \frac{d}{dt} \left(t\right)\right)}$$套用冪次法則 $$$\frac{d}{dt} \left(t^{m}\right) = m t^{m - 1}$$$，取 $$$m = 1$$$，也就是 $$$\frac{d}{dt} \left(t\right) = 1$$$：
$$i k n t_{1} {\color{red}\left(\frac{d}{dt} \left(t\right)\right)} = i k n t_{1} {\color{red}\left(1\right)}$$因此，$$$\frac{d}{dt} \left(i k n t t_{1}\right) = i k n t_{1}$$$。
答案
$$$\frac{d}{dt} \left(i k n t t_{1}\right) = i k n t_{1}$$$A
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