$$$e^{x} + \sin{\left(y z \right)}$$$ 對 $$$y$$$ 的導數
您的輸入
求$$$\frac{d}{dy} \left(e^{x} + \sin{\left(y z \right)}\right)$$$。
解答
和/差的導數等於導數的和/差:
$${\color{red}\left(\frac{d}{dy} \left(e^{x} + \sin{\left(y z \right)}\right)\right)} = {\color{red}\left(\frac{d}{dy} \left(e^{x}\right) + \frac{d}{dy} \left(\sin{\left(y z \right)}\right)\right)}$$函數 $$$\sin{\left(y z \right)}$$$ 是兩個函數 $$$f{\left(u \right)} = \sin{\left(u \right)}$$$ 與 $$$g{\left(y \right)} = y z$$$ 之複合 $$$f{\left(g{\left(y \right)} \right)}$$$。
應用鏈式法則 $$$\frac{d}{dy} \left(f{\left(g{\left(y \right)} \right)}\right) = \frac{d}{du} \left(f{\left(u \right)}\right) \frac{d}{dy} \left(g{\left(y \right)}\right)$$$:
$${\color{red}\left(\frac{d}{dy} \left(\sin{\left(y z \right)}\right)\right)} + \frac{d}{dy} \left(e^{x}\right) = {\color{red}\left(\frac{d}{du} \left(\sin{\left(u \right)}\right) \frac{d}{dy} \left(y z\right)\right)} + \frac{d}{dy} \left(e^{x}\right)$$正弦函數的導數為$$$\frac{d}{du} \left(\sin{\left(u \right)}\right) = \cos{\left(u \right)}$$$:
$${\color{red}\left(\frac{d}{du} \left(\sin{\left(u \right)}\right)\right)} \frac{d}{dy} \left(y z\right) + \frac{d}{dy} \left(e^{x}\right) = {\color{red}\left(\cos{\left(u \right)}\right)} \frac{d}{dy} \left(y z\right) + \frac{d}{dy} \left(e^{x}\right)$$返回原變數:
$$\cos{\left({\color{red}\left(u\right)} \right)} \frac{d}{dy} \left(y z\right) + \frac{d}{dy} \left(e^{x}\right) = \cos{\left({\color{red}\left(y z\right)} \right)} \frac{d}{dy} \left(y z\right) + \frac{d}{dy} \left(e^{x}\right)$$套用常數倍法則 $$$\frac{d}{dy} \left(c f{\left(y \right)}\right) = c \frac{d}{dy} \left(f{\left(y \right)}\right)$$$,使用 $$$c = z$$$ 與 $$$f{\left(y \right)} = y$$$:
$$\cos{\left(y z \right)} {\color{red}\left(\frac{d}{dy} \left(y z\right)\right)} + \frac{d}{dy} \left(e^{x}\right) = \cos{\left(y z \right)} {\color{red}\left(z \frac{d}{dy} \left(y\right)\right)} + \frac{d}{dy} \left(e^{x}\right)$$常數的導數為$$$0$$$:
$$z \cos{\left(y z \right)} \frac{d}{dy} \left(y\right) + {\color{red}\left(\frac{d}{dy} \left(e^{x}\right)\right)} = z \cos{\left(y z \right)} \frac{d}{dy} \left(y\right) + {\color{red}\left(0\right)}$$套用冪次法則 $$$\frac{d}{dy} \left(y^{n}\right) = n y^{n - 1}$$$,取 $$$n = 1$$$,也就是 $$$\frac{d}{dy} \left(y\right) = 1$$$:
$$z \cos{\left(y z \right)} {\color{red}\left(\frac{d}{dy} \left(y\right)\right)} = z \cos{\left(y z \right)} {\color{red}\left(1\right)}$$因此,$$$\frac{d}{dy} \left(e^{x} + \sin{\left(y z \right)}\right) = z \cos{\left(y z \right)}$$$。
答案
$$$\frac{d}{dy} \left(e^{x} + \sin{\left(y z \right)}\right) = z \cos{\left(y z \right)}$$$A