$$$\mathbf{\vec{r}\left(t\right)} = \left\langle \sin{\left(2 t \right)}, \cos{\left(2 t \right)}, t\right\rangle$$$ 的挠率

该计算器将求出$$$\mathbf{\vec{r}\left(t\right)} = \left\langle \sin{\left(2 t \right)}, \cos{\left(2 t \right)}, t\right\rangle$$$的挠率,并显示步骤。

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您的输入

$$$\mathbf{\vec{r}\left(t\right)} = \left\langle \sin{\left(2 t \right)}, \cos{\left(2 t \right)}, t\right\rangle$$$的挠率。

解答

$$$\mathbf{\vec{r}\left(t\right)}$$$的导数:$$$\mathbf{\vec{r}^{\prime}\left(t\right)} = \left\langle 2 \cos{\left(2 t \right)}, - 2 \sin{\left(2 t \right)}, 1\right\rangle$$$(步骤参见derivative calculator)。

$$$\mathbf{\vec{r}^{\prime}\left(t\right)}$$$的导数:$$$\mathbf{\vec{r}^{\prime\prime}\left(t\right)} = \left\langle - 4 \sin{\left(2 t \right)}, - 4 \cos{\left(2 t \right)}, 0\right\rangle$$$(步骤参见derivative calculator)。

求叉积:$$$\mathbf{\vec{r}^{\prime}\left(t\right)}\times \mathbf{\vec{r}^{\prime\prime}\left(t\right)} = \left\langle 4 \cos{\left(2 t \right)}, - 4 \sin{\left(2 t \right)}, -8\right\rangle$$$(步骤详见叉积计算器)。

$$$\mathbf{\vec{r}^{\prime}\left(t\right)}\times \mathbf{\vec{r}^{\prime\prime}\left(t\right)}$$$的模长:$$$\mathbf{\left\lvert \mathbf{\vec{r}^{\prime}\left(t\right)}\times \mathbf{\vec{r}^{\prime\prime}\left(t\right)}\right\rvert} = 4 \sqrt{5}$$$(步骤见模长计算器)。

$$$\mathbf{\vec{r}^{\prime\prime}\left(t\right)}$$$的导数:$$$\mathbf{\vec{r}^{\prime\prime\prime}\left(t\right)} = \left\langle - 8 \cos{\left(2 t \right)}, 8 \sin{\left(2 t \right)}, 0\right\rangle$$$(步骤参见derivative calculator)。

求点积:$$$\left(\mathbf{\vec{r}^{\prime}\left(t\right)}\times \mathbf{\vec{r}^{\prime\prime}\left(t\right)}\right)\cdot \mathbf{\vec{r}^{\prime\prime\prime}\left(t\right)} = -32$$$(步骤参见 点积计算器)。

最后,挠率为$$$\tau\left(t\right) = \frac{\left(\mathbf{\vec{r}^{\prime}\left(t\right)}\times \mathbf{\vec{r}^{\prime\prime}\left(t\right)}\right)\cdot \mathbf{\vec{r}^{\prime\prime\prime}\left(t\right)}}{\mathbf{\left\lvert \mathbf{\vec{r}^{\prime}\left(t\right)}\times \mathbf{\vec{r}^{\prime\prime}\left(t\right)}\right\rvert}^{2}} = - \frac{2}{5}$$$

答案

挠率为$$$\tau\left(t\right) = - \frac{2}{5}$$$A


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