$$$-8$$$ 的积分
您的输入
求$$$\int \left(-8\right)\, dx$$$。
解答
应用常数法则 $$$\int c\, dx = c x$$$,使用 $$$c=-8$$$:
$${\color{red}{\int{\left(-8\right)d x}}} = {\color{red}{\left(- 8 x\right)}}$$
因此,
$$\int{\left(-8\right)d x} = - 8 x$$
加上积分常数:
$$\int{\left(-8\right)d x} = - 8 x+C$$
答案
$$$\int \left(-8\right)\, dx = - 8 x + C$$$A
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