Integral of $$$-8$$$
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Your Input
Find $$$\int \left(-8\right)\, dx$$$.
Solution
Apply the constant rule $$$\int c\, dx = c x$$$ with $$$c=-8$$$:
$${\color{red}{\int{\left(-8\right)d x}}} = {\color{red}{\left(- 8 x\right)}}$$
Therefore,
$$\int{\left(-8\right)d x} = - 8 x$$
Add the constant of integration:
$$\int{\left(-8\right)d x} = - 8 x+C$$
Answer
$$$\int \left(-8\right)\, dx = - 8 x + C$$$A
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