定积分与广义积分计算器
逐步计算定积分和广义积分
该计算器将尝试计算定积分(即带上下限的积分),包括广义积分,并显示求解步骤。
Solution
Your input: calculate $$$\int_{0}^{3}\left( \sqrt{2} x^{3} \right)dx$$$
First, calculate the corresponding indefinite integral: $$$\int{\sqrt{2} x^{3} d x}=\frac{\sqrt{2} x^{4}}{4}$$$ (for steps, see indefinite integral calculator)
According to the Fundamental Theorem of Calculus, $$$\int_a^b F(x) dx=f(b)-f(a)$$$, so just evaluate the integral at the endpoints, and that's the answer.
$$$\left(\frac{\sqrt{2} x^{4}}{4}\right)|_{\left(x=3\right)}=\frac{81 \sqrt{2}}{4}$$$
$$$\left(\frac{\sqrt{2} x^{4}}{4}\right)|_{\left(x=0\right)}=0$$$
$$$\int_{0}^{3}\left( \sqrt{2} x^{3} \right)dx=\left(\frac{\sqrt{2} x^{4}}{4}\right)|_{\left(x=3\right)}-\left(\frac{\sqrt{2} x^{4}}{4}\right)|_{\left(x=0\right)}=\frac{81 \sqrt{2}}{4}$$$
Answer: $$$\int_{0}^{3}\left( \sqrt{2} x^{3} \right)dx=\frac{81 \sqrt{2}}{4}\approx 28.6378246380552$$$