Integralen av $$$\csc{\left(\theta \right)}$$$

Bestäm $$$\int \csc{\left(\theta \right)}\, d\theta$$$.

Skriv om kosekansen som $$$\csc\left(\theta\right)=\frac{1}{\sin\left(\theta\right)}$$$:

$${\color{red}{\int{\csc{\left(\theta \right)} d \theta}}} = {\color{red}{\int{\frac{1}{\sin{\left(\theta \right)}} d \theta}}}$$

Skriv om sinus med hjälp av dubbelvinkelformeln $$$\sin\left(\theta\right)=2\sin\left(\frac{\theta}{2}\right)\cos\left(\frac{\theta}{2}\right)$$$:

$${\color{red}{\int{\frac{1}{\sin{\left(\theta \right)}} d \theta}}} = {\color{red}{\int{\frac{1}{2 \sin{\left(\frac{\theta}{2} \right)} \cos{\left(\frac{\theta}{2} \right)}} d \theta}}}$$

Multiplicera täljare och nämnare med $$$\sec^2\left(\frac{\theta}{2} \right)$$$:

$${\color{red}{\int{\frac{1}{2 \sin{\left(\frac{\theta}{2} \right)} \cos{\left(\frac{\theta}{2} \right)}} d \theta}}} = {\color{red}{\int{\frac{\sec^{2}{\left(\frac{\theta}{2} \right)}}{2 \tan{\left(\frac{\theta}{2} \right)}} d \theta}}}$$

Låt $$$u=\tan{\left(\frac{\theta}{2} \right)}$$$ vara.

Då $$$du=\left(\tan{\left(\frac{\theta}{2} \right)}\right)^{\prime }d\theta = \frac{\sec^{2}{\left(\frac{\theta}{2} \right)}}{2} d\theta$$$ (stegen kan ses »), och vi har att $$$\sec^{2}{\left(\frac{\theta}{2} \right)} d\theta = 2 du$$$.

Alltså,

$${\color{red}{\int{\frac{\sec^{2}{\left(\frac{\theta}{2} \right)}}{2 \tan{\left(\frac{\theta}{2} \right)}} d \theta}}} = {\color{red}{\int{\frac{1}{u} d u}}}$$

Integralen av $$$\frac{1}{u}$$$ är $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:

$${\color{red}{\int{\frac{1}{u} d u}}} = {\color{red}{\ln{\left(\left|{u}\right| \right)}}}$$

Kom ihåg att $$$u=\tan{\left(\frac{\theta}{2} \right)}$$$:

$$\ln{\left(\left|{{\color{red}{u}}}\right| \right)} = \ln{\left(\left|{{\color{red}{\tan{\left(\frac{\theta}{2} \right)}}}}\right| \right)}$$

Alltså,

$$\int{\csc{\left(\theta \right)} d \theta} = \ln{\left(\left|{\tan{\left(\frac{\theta}{2} \right)}}\right| \right)}$$

Lägg till integrationskonstanten:

$$\int{\csc{\left(\theta \right)} d \theta} = \ln{\left(\left|{\tan{\left(\frac{\theta}{2} \right)}}\right| \right)}+C$$

$$$\int \csc{\left(\theta \right)}\, d\theta = \ln\left(\left|{\tan{\left(\frac{\theta}{2} \right)}}\right|\right) + C$$$A