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Integral de $$$w^{2} \ln\left(w\right)$$$
Calculadora relacionada: Calculadora de Integrais Definidas e Impróprias
Sua entrada
Encontre $$$\int w^{2} \ln\left(w\right)\, dw$$$.
Solução
Para a integral $$$\int{w^{2} \ln{\left(w \right)} d w}$$$, use integração por partes $$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$.
Sejam $$$\operatorname{u}=\ln{\left(w \right)}$$$ e $$$\operatorname{dv}=w^{2} dw$$$.
Então $$$\operatorname{du}=\left(\ln{\left(w \right)}\right)^{\prime }dw=\frac{dw}{w}$$$ (os passos podem ser vistos ») e $$$\operatorname{v}=\int{w^{2} d w}=\frac{w^{3}}{3}$$$ (os passos podem ser vistos »).
Assim,
$${\color{red}{\int{w^{2} \ln{\left(w \right)} d w}}}={\color{red}{\left(\ln{\left(w \right)} \cdot \frac{w^{3}}{3}-\int{\frac{w^{3}}{3} \cdot \frac{1}{w} d w}\right)}}={\color{red}{\left(\frac{w^{3} \ln{\left(w \right)}}{3} - \int{\frac{w^{2}}{3} d w}\right)}}$$
Aplique a regra do múltiplo constante $$$\int c f{\left(w \right)}\, dw = c \int f{\left(w \right)}\, dw$$$ usando $$$c=\frac{1}{3}$$$ e $$$f{\left(w \right)} = w^{2}$$$:
$$\frac{w^{3} \ln{\left(w \right)}}{3} - {\color{red}{\int{\frac{w^{2}}{3} d w}}} = \frac{w^{3} \ln{\left(w \right)}}{3} - {\color{red}{\left(\frac{\int{w^{2} d w}}{3}\right)}}$$
Aplique a regra da potência $$$\int w^{n}\, dw = \frac{w^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=2$$$:
$$\frac{w^{3} \ln{\left(w \right)}}{3} - \frac{{\color{red}{\int{w^{2} d w}}}}{3}=\frac{w^{3} \ln{\left(w \right)}}{3} - \frac{{\color{red}{\frac{w^{1 + 2}}{1 + 2}}}}{3}=\frac{w^{3} \ln{\left(w \right)}}{3} - \frac{{\color{red}{\left(\frac{w^{3}}{3}\right)}}}{3}$$
Portanto,
$$\int{w^{2} \ln{\left(w \right)} d w} = \frac{w^{3} \ln{\left(w \right)}}{3} - \frac{w^{3}}{9}$$
Simplifique:
$$\int{w^{2} \ln{\left(w \right)} d w} = \frac{w^{3} \left(3 \ln{\left(w \right)} - 1\right)}{9}$$
Adicione a constante de integração:
$$\int{w^{2} \ln{\left(w \right)} d w} = \frac{w^{3} \left(3 \ln{\left(w \right)} - 1\right)}{9}+C$$
Resposta
$$$\int w^{2} \ln\left(w\right)\, dw = \frac{w^{3} \left(3 \ln\left(w\right) - 1\right)}{9} + C$$$A