Integral de $$$\frac{4 t_{1}}{x_{1}^{2}}$$$ em relação a $$$t_{1}$$$

Encontre $$$\int \frac{4 t_{1}}{x_{1}^{2}}\, dt_{1}$$$.

Aplique a regra do múltiplo constante $$$\int c f{\left(t_{1} \right)}\, dt_{1} = c \int f{\left(t_{1} \right)}\, dt_{1}$$$ usando $$$c=\frac{4}{x_{1}^{2}}$$$ e $$$f{\left(t_{1} \right)} = t_{1}$$$:

$${\color{red}{\int{\frac{4 t_{1}}{x_{1}^{2}} d t_{1}}}} = {\color{red}{\left(\frac{4 \int{t_{1} d t_{1}}}{x_{1}^{2}}\right)}}$$

Aplique a regra da potência $$$\int t_{1}^{n}\, dt_{1} = \frac{t_{1}^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=1$$$:

$$\frac{4 {\color{red}{\int{t_{1} d t_{1}}}}}{x_{1}^{2}}=\frac{4 {\color{red}{\frac{t_{1}^{1 + 1}}{1 + 1}}}}{x_{1}^{2}}=\frac{4 {\color{red}{\left(\frac{t_{1}^{2}}{2}\right)}}}{x_{1}^{2}}$$

Portanto,

$$\int{\frac{4 t_{1}}{x_{1}^{2}} d t_{1}} = \frac{2 t_{1}^{2}}{x_{1}^{2}}$$

Adicione a constante de integração:

$$\int{\frac{4 t_{1}}{x_{1}^{2}} d t_{1}} = \frac{2 t_{1}^{2}}{x_{1}^{2}}+C$$

$$$\int \frac{4 t_{1}}{x_{1}^{2}}\, dt_{1} = \frac{2 t_{1}^{2}}{x_{1}^{2}} + C$$$A