Integral de $$$- \sqrt{x} + x$$$

Encontre $$$\int \left(- \sqrt{x} + x\right)\, dx$$$.

Integre termo a termo:

$${\color{red}{\int{\left(- \sqrt{x} + x\right)d x}}} = {\color{red}{\left(- \int{\sqrt{x} d x} + \int{x d x}\right)}}$$

Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=1$$$:

$$- \int{\sqrt{x} d x} + {\color{red}{\int{x d x}}}=- \int{\sqrt{x} d x} + {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=- \int{\sqrt{x} d x} + {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=\frac{1}{2}$$$:

$$\frac{x^{2}}{2} - {\color{red}{\int{\sqrt{x} d x}}}=\frac{x^{2}}{2} - {\color{red}{\int{x^{\frac{1}{2}} d x}}}=\frac{x^{2}}{2} - {\color{red}{\frac{x^{\frac{1}{2} + 1}}{\frac{1}{2} + 1}}}=\frac{x^{2}}{2} - {\color{red}{\left(\frac{2 x^{\frac{3}{2}}}{3}\right)}}$$

Portanto,

$$\int{\left(- \sqrt{x} + x\right)d x} = - \frac{2 x^{\frac{3}{2}}}{3} + \frac{x^{2}}{2}$$

Adicione a constante de integração:

$$\int{\left(- \sqrt{x} + x\right)d x} = - \frac{2 x^{\frac{3}{2}}}{3} + \frac{x^{2}}{2}+C$$

$$$\int \left(- \sqrt{x} + x\right)\, dx = \left(- \frac{2 x^{\frac{3}{2}}}{3} + \frac{x^{2}}{2}\right) + C$$$A