Integral de $$$\sqrt{3} \sqrt{x}$$$

Encontre $$$\int \sqrt{3} \sqrt{x}\, dx$$$.

Aplique a regra do múltiplo constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ usando $$$c=\sqrt{3}$$$ e $$$f{\left(x \right)} = \sqrt{x}$$$:

$${\color{red}{\int{\sqrt{3} \sqrt{x} d x}}} = {\color{red}{\sqrt{3} \int{\sqrt{x} d x}}}$$

Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=\frac{1}{2}$$$:

$$\sqrt{3} {\color{red}{\int{\sqrt{x} d x}}}=\sqrt{3} {\color{red}{\int{x^{\frac{1}{2}} d x}}}=\sqrt{3} {\color{red}{\frac{x^{\frac{1}{2} + 1}}{\frac{1}{2} + 1}}}=\sqrt{3} {\color{red}{\left(\frac{2 x^{\frac{3}{2}}}{3}\right)}}$$

Portanto,

$$\int{\sqrt{3} \sqrt{x} d x} = \frac{2 \sqrt{3} x^{\frac{3}{2}}}{3}$$

Adicione a constante de integração:

$$\int{\sqrt{3} \sqrt{x} d x} = \frac{2 \sqrt{3} x^{\frac{3}{2}}}{3}+C$$

$$$\int \sqrt{3} \sqrt{x}\, dx = \frac{2 \sqrt{3} x^{\frac{3}{2}}}{3} + C$$$A