Integral de $$$\csc{\left(x \right)}$$$
Calculadora relacionada: Calculadora de Integrais Definidas e Impróprias
Sua entrada
Encontre $$$\int \csc{\left(x \right)}\, dx$$$.
Solução
Reescreva a cossecante como $$$\csc\left(x\right)=\frac{1}{\sin\left(x\right)}$$$:
$${\color{red}{\int{\csc{\left(x \right)} d x}}} = {\color{red}{\int{\frac{1}{\sin{\left(x \right)}} d x}}}$$
Reescreva o seno usando a fórmula do ângulo duplo $$$\sin\left(x\right)=2\sin\left(\frac{x}{2}\right)\cos\left(\frac{x}{2}\right)$$$:
$${\color{red}{\int{\frac{1}{\sin{\left(x \right)}} d x}}} = {\color{red}{\int{\frac{1}{2 \sin{\left(\frac{x}{2} \right)} \cos{\left(\frac{x}{2} \right)}} d x}}}$$
Multiplique o numerador e o denominador por $$$\sec^2\left(\frac{x}{2} \right)$$$:
$${\color{red}{\int{\frac{1}{2 \sin{\left(\frac{x}{2} \right)} \cos{\left(\frac{x}{2} \right)}} d x}}} = {\color{red}{\int{\frac{\sec^{2}{\left(\frac{x}{2} \right)}}{2 \tan{\left(\frac{x}{2} \right)}} d x}}}$$
Seja $$$u=\tan{\left(\frac{x}{2} \right)}$$$.
Então $$$du=\left(\tan{\left(\frac{x}{2} \right)}\right)^{\prime }dx = \frac{\sec^{2}{\left(\frac{x}{2} \right)}}{2} dx$$$ (veja os passos »), e obtemos $$$\sec^{2}{\left(\frac{x}{2} \right)} dx = 2 du$$$.
Portanto,
$${\color{red}{\int{\frac{\sec^{2}{\left(\frac{x}{2} \right)}}{2 \tan{\left(\frac{x}{2} \right)}} d x}}} = {\color{red}{\int{\frac{1}{u} d u}}}$$
A integral de $$$\frac{1}{u}$$$ é $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:
$${\color{red}{\int{\frac{1}{u} d u}}} = {\color{red}{\ln{\left(\left|{u}\right| \right)}}}$$
Recorde que $$$u=\tan{\left(\frac{x}{2} \right)}$$$:
$$\ln{\left(\left|{{\color{red}{u}}}\right| \right)} = \ln{\left(\left|{{\color{red}{\tan{\left(\frac{x}{2} \right)}}}}\right| \right)}$$
Portanto,
$$\int{\csc{\left(x \right)} d x} = \ln{\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right| \right)}$$
Adicione a constante de integração:
$$\int{\csc{\left(x \right)} d x} = \ln{\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right| \right)}+C$$
Resposta
$$$\int \csc{\left(x \right)}\, dx = \ln\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right|\right) + C$$$A