Integral de $$$\cos{\left(4 t \right)}$$$

Encontre $$$\int \cos{\left(4 t \right)}\, dt$$$.

Seja $$$u=4 t$$$.

Então $$$du=\left(4 t\right)^{\prime }dt = 4 dt$$$ (veja os passos »), e obtemos $$$dt = \frac{du}{4}$$$.

A integral pode ser reescrita como

$${\color{red}{\int{\cos{\left(4 t \right)} d t}}} = {\color{red}{\int{\frac{\cos{\left(u \right)}}{4} d u}}}$$

Aplique a regra do múltiplo constante $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ usando $$$c=\frac{1}{4}$$$ e $$$f{\left(u \right)} = \cos{\left(u \right)}$$$:

$${\color{red}{\int{\frac{\cos{\left(u \right)}}{4} d u}}} = {\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{4}\right)}}$$

A integral do cosseno é $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:

$$\frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{4} = \frac{{\color{red}{\sin{\left(u \right)}}}}{4}$$

Recorde que $$$u=4 t$$$:

$$\frac{\sin{\left({\color{red}{u}} \right)}}{4} = \frac{\sin{\left({\color{red}{\left(4 t\right)}} \right)}}{4}$$

Portanto,

$$\int{\cos{\left(4 t \right)} d t} = \frac{\sin{\left(4 t \right)}}{4}$$

Adicione a constante de integração:

$$\int{\cos{\left(4 t \right)} d t} = \frac{\sin{\left(4 t \right)}}{4}+C$$

$$$\int \cos{\left(4 t \right)}\, dt = \frac{\sin{\left(4 t \right)}}{4} + C$$$A