Integral de $$$4 x^{2} - 3$$$

Encontre $$$\int \left(4 x^{2} - 3\right)\, dx$$$.

Integre termo a termo:

$${\color{red}{\int{\left(4 x^{2} - 3\right)d x}}} = {\color{red}{\left(- \int{3 d x} + \int{4 x^{2} d x}\right)}}$$

Aplique a regra da constante $$$\int c\, dx = c x$$$ usando $$$c=3$$$:

$$\int{4 x^{2} d x} - {\color{red}{\int{3 d x}}} = \int{4 x^{2} d x} - {\color{red}{\left(3 x\right)}}$$

Aplique a regra do múltiplo constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ usando $$$c=4$$$ e $$$f{\left(x \right)} = x^{2}$$$:

$$- 3 x + {\color{red}{\int{4 x^{2} d x}}} = - 3 x + {\color{red}{\left(4 \int{x^{2} d x}\right)}}$$

Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=2$$$:

$$- 3 x + 4 {\color{red}{\int{x^{2} d x}}}=- 3 x + 4 {\color{red}{\frac{x^{1 + 2}}{1 + 2}}}=- 3 x + 4 {\color{red}{\left(\frac{x^{3}}{3}\right)}}$$

Portanto,

$$\int{\left(4 x^{2} - 3\right)d x} = \frac{4 x^{3}}{3} - 3 x$$

Simplifique:

$$\int{\left(4 x^{2} - 3\right)d x} = \frac{x \left(4 x^{2} - 9\right)}{3}$$

Adicione a constante de integração:

$$\int{\left(4 x^{2} - 3\right)d x} = \frac{x \left(4 x^{2} - 9\right)}{3}+C$$

$$$\int \left(4 x^{2} - 3\right)\, dx = \frac{x \left(4 x^{2} - 9\right)}{3} + C$$$A