Integral de $$$\frac{363 x}{e^{\frac{109}{1000}}}$$$

Encontre $$$\int \frac{363 x}{e^{\frac{109}{1000}}}\, dx$$$.

Aplique a regra do múltiplo constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ usando $$$c=\frac{363}{e^{\frac{109}{1000}}}$$$ e $$$f{\left(x \right)} = x$$$:

$${\color{red}{\int{\frac{363 x}{e^{\frac{109}{1000}}} d x}}} = {\color{red}{\left(\frac{363 \int{x d x}}{e^{\frac{109}{1000}}}\right)}}$$

Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=1$$$:

$$\frac{363 {\color{red}{\int{x d x}}}}{e^{\frac{109}{1000}}}=\frac{363 {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}}{e^{\frac{109}{1000}}}=\frac{363 {\color{red}{\left(\frac{x^{2}}{2}\right)}}}{e^{\frac{109}{1000}}}$$

Portanto,

$$\int{\frac{363 x}{e^{\frac{109}{1000}}} d x} = \frac{363 x^{2}}{2 e^{\frac{109}{1000}}}$$

Adicione a constante de integração:

$$\int{\frac{363 x}{e^{\frac{109}{1000}}} d x} = \frac{363 x^{2}}{2 e^{\frac{109}{1000}}}+C$$

$$$\int \frac{363 x}{e^{\frac{109}{1000}}}\, dx = \frac{363 x^{2}}{2 e^{\frac{109}{1000}}} + C$$$A