Integral de $$$160 t^{3}$$$

Encontre $$$\int 160 t^{3}\, dt$$$.

Aplique a regra do múltiplo constante $$$\int c f{\left(t \right)}\, dt = c \int f{\left(t \right)}\, dt$$$ usando $$$c=160$$$ e $$$f{\left(t \right)} = t^{3}$$$:

$${\color{red}{\int{160 t^{3} d t}}} = {\color{red}{\left(160 \int{t^{3} d t}\right)}}$$

Aplique a regra da potência $$$\int t^{n}\, dt = \frac{t^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=3$$$:

$$160 {\color{red}{\int{t^{3} d t}}}=160 {\color{red}{\frac{t^{1 + 3}}{1 + 3}}}=160 {\color{red}{\left(\frac{t^{4}}{4}\right)}}$$

Portanto,

$$\int{160 t^{3} d t} = 40 t^{4}$$

Adicione a constante de integração:

$$\int{160 t^{3} d t} = 40 t^{4}+C$$

$$$\int 160 t^{3}\, dt = 40 t^{4} + C$$$A