Integral de $$$- x e^{2} + 1$$$

Encontre $$$\int \left(- x e^{2} + 1\right)\, dx$$$.

Integre termo a termo:

$${\color{red}{\int{\left(- x e^{2} + 1\right)d x}}} = {\color{red}{\left(\int{1 d x} - \int{x e^{2} d x}\right)}}$$

Aplique a regra da constante $$$\int c\, dx = c x$$$ usando $$$c=1$$$:

$$- \int{x e^{2} d x} + {\color{red}{\int{1 d x}}} = - \int{x e^{2} d x} + {\color{red}{x}}$$

Aplique a regra do múltiplo constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ usando $$$c=e^{2}$$$ e $$$f{\left(x \right)} = x$$$:

$$x - {\color{red}{\int{x e^{2} d x}}} = x - {\color{red}{e^{2} \int{x d x}}}$$

Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=1$$$:

$$x - e^{2} {\color{red}{\int{x d x}}}=x - e^{2} {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=x - e^{2} {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

Portanto,

$$\int{\left(- x e^{2} + 1\right)d x} = - \frac{x^{2} e^{2}}{2} + x$$

Simplifique:

$$\int{\left(- x e^{2} + 1\right)d x} = \frac{x \left(- x e^{2} + 2\right)}{2}$$

Adicione a constante de integração:

$$\int{\left(- x e^{2} + 1\right)d x} = \frac{x \left(- x e^{2} + 2\right)}{2}+C$$

$$$\int \left(- x e^{2} + 1\right)\, dx = \frac{x \left(- x e^{2} + 2\right)}{2} + C$$$A