Integral de $$$\frac{1}{x^{202667}}$$$

Encontre $$$\int \frac{1}{x^{202667}}\, dx$$$.

Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=-202667$$$:

$${\color{red}{\int{\frac{1}{x^{202667}} d x}}}={\color{red}{\int{x^{-202667} d x}}}={\color{red}{\frac{x^{-202667 + 1}}{-202667 + 1}}}={\color{red}{\left(- \frac{x^{-202666}}{202666}\right)}}={\color{red}{\left(- \frac{1}{202666 x^{202666}}\right)}}$$

Portanto,

$$\int{\frac{1}{x^{202667}} d x} = - \frac{1}{202666 x^{202666}}$$

Adicione a constante de integração:

$$\int{\frac{1}{x^{202667}} d x} = - \frac{1}{202666 x^{202666}}+C$$

$$$\int \frac{1}{x^{202667}}\, dx = - \frac{1}{202666 x^{202666}} + C$$$A