Integral de $$$17 - 2 x$$$

Encontre $$$\int \left(17 - 2 x\right)\, dx$$$.

Integre termo a termo:

$${\color{red}{\int{\left(17 - 2 x\right)d x}}} = {\color{red}{\left(\int{17 d x} - \int{2 x d x}\right)}}$$

Aplique a regra da constante $$$\int c\, dx = c x$$$ usando $$$c=17$$$:

$$- \int{2 x d x} + {\color{red}{\int{17 d x}}} = - \int{2 x d x} + {\color{red}{\left(17 x\right)}}$$

Aplique a regra do múltiplo constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ usando $$$c=2$$$ e $$$f{\left(x \right)} = x$$$:

$$17 x - {\color{red}{\int{2 x d x}}} = 17 x - {\color{red}{\left(2 \int{x d x}\right)}}$$

Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=1$$$:

$$17 x - 2 {\color{red}{\int{x d x}}}=17 x - 2 {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=17 x - 2 {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

Portanto,

$$\int{\left(17 - 2 x\right)d x} = - x^{2} + 17 x$$

Simplifique:

$$\int{\left(17 - 2 x\right)d x} = x \left(17 - x\right)$$

Adicione a constante de integração:

$$\int{\left(17 - 2 x\right)d x} = x \left(17 - x\right)+C$$

$$$\int \left(17 - 2 x\right)\, dx = x \left(17 - x\right) + C$$$A