Integral de $$$\frac{d}{t^{5}}$$$ em relação a $$$t$$$

Encontre $$$\int \frac{d}{t^{5}}\, dt$$$.

Aplique a regra do múltiplo constante $$$\int c f{\left(t \right)}\, dt = c \int f{\left(t \right)}\, dt$$$ usando $$$c=d$$$ e $$$f{\left(t \right)} = \frac{1}{t^{5}}$$$:

$${\color{red}{\int{\frac{d}{t^{5}} d t}}} = {\color{red}{d \int{\frac{1}{t^{5}} d t}}}$$

Aplique a regra da potência $$$\int t^{n}\, dt = \frac{t^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=-5$$$:

$$d {\color{red}{\int{\frac{1}{t^{5}} d t}}}=d {\color{red}{\int{t^{-5} d t}}}=d {\color{red}{\frac{t^{-5 + 1}}{-5 + 1}}}=d {\color{red}{\left(- \frac{t^{-4}}{4}\right)}}=d {\color{red}{\left(- \frac{1}{4 t^{4}}\right)}}$$

Portanto,

$$\int{\frac{d}{t^{5}} d t} = - \frac{d}{4 t^{4}}$$

Adicione a constante de integração:

$$\int{\frac{d}{t^{5}} d t} = - \frac{d}{4 t^{4}}+C$$

$$$\int \frac{d}{t^{5}}\, dt = - \frac{d}{4 t^{4}} + C$$$A