Integral de $$$\left(1 - u^{2}\right)^{2}$$$
Calculadora relacionada: Calculadora de Integrais Definidas e Impróprias
Sua entrada
Encontre $$$\int \left(1 - u^{2}\right)^{2}\, du$$$.
Solução
Expand the expression:
$${\color{red}{\int{\left(1 - u^{2}\right)^{2} d u}}} = {\color{red}{\int{\left(u^{4} - 2 u^{2} + 1\right)d u}}}$$
Integre termo a termo:
$${\color{red}{\int{\left(u^{4} - 2 u^{2} + 1\right)d u}}} = {\color{red}{\left(\int{1 d u} - \int{2 u^{2} d u} + \int{u^{4} d u}\right)}}$$
Aplique a regra da constante $$$\int c\, du = c u$$$ usando $$$c=1$$$:
$$- \int{2 u^{2} d u} + \int{u^{4} d u} + {\color{red}{\int{1 d u}}} = - \int{2 u^{2} d u} + \int{u^{4} d u} + {\color{red}{u}}$$
Aplique a regra da potência $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=4$$$:
$$u - \int{2 u^{2} d u} + {\color{red}{\int{u^{4} d u}}}=u - \int{2 u^{2} d u} + {\color{red}{\frac{u^{1 + 4}}{1 + 4}}}=u - \int{2 u^{2} d u} + {\color{red}{\left(\frac{u^{5}}{5}\right)}}$$
Aplique a regra do múltiplo constante $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ usando $$$c=2$$$ e $$$f{\left(u \right)} = u^{2}$$$:
$$\frac{u^{5}}{5} + u - {\color{red}{\int{2 u^{2} d u}}} = \frac{u^{5}}{5} + u - {\color{red}{\left(2 \int{u^{2} d u}\right)}}$$
Aplique a regra da potência $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=2$$$:
$$\frac{u^{5}}{5} + u - 2 {\color{red}{\int{u^{2} d u}}}=\frac{u^{5}}{5} + u - 2 {\color{red}{\frac{u^{1 + 2}}{1 + 2}}}=\frac{u^{5}}{5} + u - 2 {\color{red}{\left(\frac{u^{3}}{3}\right)}}$$
Portanto,
$$\int{\left(1 - u^{2}\right)^{2} d u} = \frac{u^{5}}{5} - \frac{2 u^{3}}{3} + u$$
Adicione a constante de integração:
$$\int{\left(1 - u^{2}\right)^{2} d u} = \frac{u^{5}}{5} - \frac{2 u^{3}}{3} + u+C$$
Resposta
$$$\int \left(1 - u^{2}\right)^{2}\, du = \left(\frac{u^{5}}{5} - \frac{2 u^{3}}{3} + u\right) + C$$$A