Integraal van $$$x \cos{\left(\pi n x \right)}$$$ met betrekking tot $$$x$$$
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Uw invoer
Bepaal $$$\int x \cos{\left(\pi n x \right)}\, dx$$$.
Oplossing
Voor de integraal $$$\int{x \cos{\left(\pi n x \right)} d x}$$$, gebruik partiële integratie $$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$.
Zij $$$\operatorname{u}=x$$$ en $$$\operatorname{dv}=\cos{\left(\pi n x \right)} dx$$$.
Dan $$$\operatorname{du}=\left(x\right)^{\prime }dx=1 dx$$$ (de stappen zijn te zien ») en $$$\operatorname{v}=\int{\cos{\left(\pi n x \right)} d x}=\frac{\sin{\left(\pi n x \right)}}{\pi n}$$$ (de stappen zijn te zien »).
Dus,
$${\color{red}{\int{x \cos{\left(\pi n x \right)} d x}}}={\color{red}{\left(x \cdot \frac{\sin{\left(\pi n x \right)}}{\pi n}-\int{\frac{\sin{\left(\pi n x \right)}}{\pi n} \cdot 1 d x}\right)}}={\color{red}{\left(- \int{\frac{\sin{\left(\pi n x \right)}}{\pi n} d x} + \frac{x \sin{\left(\pi n x \right)}}{\pi n}\right)}}$$
Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=\frac{1}{\pi n}$$$ en $$$f{\left(x \right)} = \sin{\left(\pi n x \right)}$$$:
$$- {\color{red}{\int{\frac{\sin{\left(\pi n x \right)}}{\pi n} d x}}} + \frac{x \sin{\left(\pi n x \right)}}{\pi n} = - {\color{red}{\frac{\int{\sin{\left(\pi n x \right)} d x}}{\pi n}}} + \frac{x \sin{\left(\pi n x \right)}}{\pi n}$$
Zij $$$u=\pi n x$$$.
Dan $$$du=\left(\pi n x\right)^{\prime }dx = \pi n dx$$$ (de stappen zijn te zien »), en dan geldt dat $$$dx = \frac{du}{\pi n}$$$.
Dus,
$$\frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\int{\sin{\left(\pi n x \right)} d x}}}}{\pi n} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{\pi n} d u}}}}{\pi n}$$
Pas de constante-veelvoudregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ toe met $$$c=\frac{1}{\pi n}$$$ en $$$f{\left(u \right)} = \sin{\left(u \right)}$$$:
$$\frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\int{\frac{\sin{\left(u \right)}}{\pi n} d u}}}}{\pi n} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\frac{\int{\sin{\left(u \right)} d u}}{\pi n}}}}{\pi n}$$
De integraal van de sinus is $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:
$$\frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{\pi^{2} n^{2}} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} - \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{\pi^{2} n^{2}}$$
We herinneren eraan dat $$$u=\pi n x$$$:
$$\frac{x \sin{\left(\pi n x \right)}}{\pi n} + \frac{\cos{\left({\color{red}{u}} \right)}}{\pi^{2} n^{2}} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} + \frac{\cos{\left({\color{red}{\pi n x}} \right)}}{\pi^{2} n^{2}}$$
Dus,
$$\int{x \cos{\left(\pi n x \right)} d x} = \frac{x \sin{\left(\pi n x \right)}}{\pi n} + \frac{\cos{\left(\pi n x \right)}}{\pi^{2} n^{2}}$$
Vereenvoudig:
$$\int{x \cos{\left(\pi n x \right)} d x} = \frac{\pi n x \sin{\left(\pi n x \right)} + \cos{\left(\pi n x \right)}}{\pi^{2} n^{2}}$$
Voeg de integratieconstante toe:
$$\int{x \cos{\left(\pi n x \right)} d x} = \frac{\pi n x \sin{\left(\pi n x \right)} + \cos{\left(\pi n x \right)}}{\pi^{2} n^{2}}+C$$
Antwoord
$$$\int x \cos{\left(\pi n x \right)}\, dx = \frac{\pi n x \sin{\left(\pi n x \right)} + \cos{\left(\pi n x \right)}}{\pi^{2} n^{2}} + C$$$A