Integraal van $$$84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)}$$$ met betrekking tot $$$x$$$
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Uw invoer
Bepaal $$$\int 84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)}\, dx$$$.
Oplossing
Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=84 i n t$$$ en $$$f{\left(x \right)} = \sin{\left(3 x \right)} \cos{\left(3 x \right)}$$$:
$${\color{red}{\int{84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)} d x}}} = {\color{red}{\left(84 i n t \int{\sin{\left(3 x \right)} \cos{\left(3 x \right)} d x}\right)}}$$
Zij $$$u=\sin{\left(3 x \right)}$$$.
Dan $$$du=\left(\sin{\left(3 x \right)}\right)^{\prime }dx = 3 \cos{\left(3 x \right)} dx$$$ (de stappen zijn te zien »), en dan geldt dat $$$\cos{\left(3 x \right)} dx = \frac{du}{3}$$$.
De integraal wordt
$$84 i n t {\color{red}{\int{\sin{\left(3 x \right)} \cos{\left(3 x \right)} d x}}} = 84 i n t {\color{red}{\int{\frac{u}{3} d u}}}$$
Pas de constante-veelvoudregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ toe met $$$c=\frac{1}{3}$$$ en $$$f{\left(u \right)} = u$$$:
$$84 i n t {\color{red}{\int{\frac{u}{3} d u}}} = 84 i n t {\color{red}{\left(\frac{\int{u d u}}{3}\right)}}$$
Pas de machtsregel $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=1$$$:
$$28 i n t {\color{red}{\int{u d u}}}=28 i n t {\color{red}{\frac{u^{1 + 1}}{1 + 1}}}=28 i n t {\color{red}{\left(\frac{u^{2}}{2}\right)}}$$
We herinneren eraan dat $$$u=\sin{\left(3 x \right)}$$$:
$$14 i n t {\color{red}{u}}^{2} = 14 i n t {\color{red}{\sin{\left(3 x \right)}}}^{2}$$
Dus,
$$\int{84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)} d x} = 14 i n t \sin^{2}{\left(3 x \right)}$$
Voeg de integratieconstante toe:
$$\int{84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)} d x} = 14 i n t \sin^{2}{\left(3 x \right)}+C$$
Antwoord
$$$\int 84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)}\, dx = 14 i n t \sin^{2}{\left(3 x \right)} + C$$$A