Integraal van $$$x^{6} + 3 x^{2} - 1$$$

Bepaal $$$\int \left(x^{6} + 3 x^{2} - 1\right)\, dx$$$.

Integreer termgewijs:

$${\color{red}{\int{\left(x^{6} + 3 x^{2} - 1\right)d x}}} = {\color{red}{\left(- \int{1 d x} + \int{3 x^{2} d x} + \int{x^{6} d x}\right)}}$$

Pas de constantenregel $$$\int c\, dx = c x$$$ toe met $$$c=1$$$:

$$\int{3 x^{2} d x} + \int{x^{6} d x} - {\color{red}{\int{1 d x}}} = \int{3 x^{2} d x} + \int{x^{6} d x} - {\color{red}{x}}$$

Pas de machtsregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=6$$$:

$$- x + \int{3 x^{2} d x} + {\color{red}{\int{x^{6} d x}}}=- x + \int{3 x^{2} d x} + {\color{red}{\frac{x^{1 + 6}}{1 + 6}}}=- x + \int{3 x^{2} d x} + {\color{red}{\left(\frac{x^{7}}{7}\right)}}$$

Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=3$$$ en $$$f{\left(x \right)} = x^{2}$$$:

$$\frac{x^{7}}{7} - x + {\color{red}{\int{3 x^{2} d x}}} = \frac{x^{7}}{7} - x + {\color{red}{\left(3 \int{x^{2} d x}\right)}}$$

Pas de machtsregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=2$$$:

$$\frac{x^{7}}{7} - x + 3 {\color{red}{\int{x^{2} d x}}}=\frac{x^{7}}{7} - x + 3 {\color{red}{\frac{x^{1 + 2}}{1 + 2}}}=\frac{x^{7}}{7} - x + 3 {\color{red}{\left(\frac{x^{3}}{3}\right)}}$$

Dus,

$$\int{\left(x^{6} + 3 x^{2} - 1\right)d x} = \frac{x^{7}}{7} + x^{3} - x$$

Voeg de integratieconstante toe:

$$\int{\left(x^{6} + 3 x^{2} - 1\right)d x} = \frac{x^{7}}{7} + x^{3} - x+C$$

$$$\int \left(x^{6} + 3 x^{2} - 1\right)\, dx = \left(\frac{x^{7}}{7} + x^{3} - x\right) + C$$$A