Integraal van $$$\frac{x}{12}$$$

Bepaal $$$\int \frac{x}{12}\, dx$$$.

Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=\frac{1}{12}$$$ en $$$f{\left(x \right)} = x$$$:

$${\color{red}{\int{\frac{x}{12} d x}}} = {\color{red}{\left(\frac{\int{x d x}}{12}\right)}}$$

Pas de machtsregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=1$$$:

$$\frac{{\color{red}{\int{x d x}}}}{12}=\frac{{\color{red}{\frac{x^{1 + 1}}{1 + 1}}}}{12}=\frac{{\color{red}{\left(\frac{x^{2}}{2}\right)}}}{12}$$

Dus,

$$\int{\frac{x}{12} d x} = \frac{x^{2}}{24}$$

Voeg de integratieconstante toe:

$$\int{\frac{x}{12} d x} = \frac{x^{2}}{24}+C$$

$$$\int \frac{x}{12}\, dx = \frac{x^{2}}{24} + C$$$A