Integraal van $$$a^{2} f^{2} x^{2} + b^{2} f$$$ met betrekking tot $$$x$$$

Bepaal $$$\int \left(a^{2} f^{2} x^{2} + b^{2} f\right)\, dx$$$.

Integreer termgewijs:

$${\color{red}{\int{\left(a^{2} f^{2} x^{2} + b^{2} f\right)d x}}} = {\color{red}{\left(\int{b^{2} f d x} + \int{a^{2} f^{2} x^{2} d x}\right)}}$$

Pas de constantenregel $$$\int c\, dx = c x$$$ toe met $$$c=b^{2} f$$$:

$$\int{a^{2} f^{2} x^{2} d x} + {\color{red}{\int{b^{2} f d x}}} = \int{a^{2} f^{2} x^{2} d x} + {\color{red}{b^{2} f x}}$$

Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=a^{2} f^{2}$$$ en $$$f{\left(x \right)} = x^{2}$$$:

$$b^{2} f x + {\color{red}{\int{a^{2} f^{2} x^{2} d x}}} = b^{2} f x + {\color{red}{a^{2} f^{2} \int{x^{2} d x}}}$$

Pas de machtsregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=2$$$:

$$a^{2} f^{2} {\color{red}{\int{x^{2} d x}}} + b^{2} f x=a^{2} f^{2} {\color{red}{\frac{x^{1 + 2}}{1 + 2}}} + b^{2} f x=a^{2} f^{2} {\color{red}{\left(\frac{x^{3}}{3}\right)}} + b^{2} f x$$

Dus,

$$\int{\left(a^{2} f^{2} x^{2} + b^{2} f\right)d x} = \frac{a^{2} f^{2} x^{3}}{3} + b^{2} f x$$

Vereenvoudig:

$$\int{\left(a^{2} f^{2} x^{2} + b^{2} f\right)d x} = \frac{f x \left(a^{2} f x^{2} + 3 b^{2}\right)}{3}$$

Voeg de integratieconstante toe:

$$\int{\left(a^{2} f^{2} x^{2} + b^{2} f\right)d x} = \frac{f x \left(a^{2} f x^{2} + 3 b^{2}\right)}{3}+C$$

$$$\int \left(a^{2} f^{2} x^{2} + b^{2} f\right)\, dx = \frac{f x \left(a^{2} f x^{2} + 3 b^{2}\right)}{3} + C$$$A