Integraal van $$$g_{3} r^{5}$$$ met betrekking tot $$$g_{3}$$$

Bepaal $$$\int g_{3} r^{5}\, dg_{3}$$$.

Pas de constante-veelvoudregel $$$\int c f{\left(g_{3} \right)}\, dg_{3} = c \int f{\left(g_{3} \right)}\, dg_{3}$$$ toe met $$$c=r^{5}$$$ en $$$f{\left(g_{3} \right)} = g_{3}$$$:

$${\color{red}{\int{g_{3} r^{5} d g_{3}}}} = {\color{red}{r^{5} \int{g_{3} d g_{3}}}}$$

Pas de machtsregel $$$\int g_{3}^{n}\, dg_{3} = \frac{g_{3}^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=1$$$:

$$r^{5} {\color{red}{\int{g_{3} d g_{3}}}}=r^{5} {\color{red}{\frac{g_{3}^{1 + 1}}{1 + 1}}}=r^{5} {\color{red}{\left(\frac{g_{3}^{2}}{2}\right)}}$$

Dus,

$$\int{g_{3} r^{5} d g_{3}} = \frac{g_{3}^{2} r^{5}}{2}$$

Voeg de integratieconstante toe:

$$\int{g_{3} r^{5} d g_{3}} = \frac{g_{3}^{2} r^{5}}{2}+C$$

$$$\int g_{3} r^{5}\, dg_{3} = \frac{g_{3}^{2} r^{5}}{2} + C$$$A