Integraal van $$$\frac{4 x^{2} - 2 \sqrt{2} x}{x}$$$

Bepaal $$$\int \frac{4 x^{2} - 2 \sqrt{2} x}{x}\, dx$$$.

Expand the expression:

$${\color{red}{\int{\frac{4 x^{2} - 2 \sqrt{2} x}{x} d x}}} = {\color{red}{\int{\left(4 x - 2 \sqrt{2}\right)d x}}}$$

Integreer termgewijs:

$${\color{red}{\int{\left(4 x - 2 \sqrt{2}\right)d x}}} = {\color{red}{\left(- \int{2 \sqrt{2} d x} + \int{4 x d x}\right)}}$$

Pas de constantenregel $$$\int c\, dx = c x$$$ toe met $$$c=2 \sqrt{2}$$$:

$$\int{4 x d x} - {\color{red}{\int{2 \sqrt{2} d x}}} = \int{4 x d x} - {\color{red}{\left(2 \sqrt{2} x\right)}}$$

Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=4$$$ en $$$f{\left(x \right)} = x$$$:

$$- 2 \sqrt{2} x + {\color{red}{\int{4 x d x}}} = - 2 \sqrt{2} x + {\color{red}{\left(4 \int{x d x}\right)}}$$

Pas de machtsregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=1$$$:

$$- 2 \sqrt{2} x + 4 {\color{red}{\int{x d x}}}=- 2 \sqrt{2} x + 4 {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=- 2 \sqrt{2} x + 4 {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

Dus,

$$\int{\frac{4 x^{2} - 2 \sqrt{2} x}{x} d x} = 2 x^{2} - 2 \sqrt{2} x$$

Vereenvoudig:

$$\int{\frac{4 x^{2} - 2 \sqrt{2} x}{x} d x} = 2 x \left(x - \sqrt{2}\right)$$

Voeg de integratieconstante toe:

$$\int{\frac{4 x^{2} - 2 \sqrt{2} x}{x} d x} = 2 x \left(x - \sqrt{2}\right)+C$$

$$$\int \frac{4 x^{2} - 2 \sqrt{2} x}{x}\, dx = 2 x \left(x - \sqrt{2}\right) + C$$$A