Integraal van $$$9^{x} \sin{\left(9^{x} \right)}$$$
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Uw invoer
Bepaal $$$\int 9^{x} \sin{\left(9^{x} \right)}\, dx$$$.
Oplossing
Zij $$$u=9^{x}$$$.
Dan $$$du=\left(9^{x}\right)^{\prime }dx = 9^{x} \ln{\left(9 \right)} dx$$$ (de stappen zijn te zien »), en dan geldt dat $$$9^{x} dx = \frac{du}{\ln{\left(9 \right)}}$$$.
Dus,
$${\color{red}{\int{9^{x} \sin{\left(9^{x} \right)} d x}}} = {\color{red}{\int{\frac{\sin{\left(u \right)}}{2 \ln{\left(3 \right)}} d u}}}$$
Pas de constante-veelvoudregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ toe met $$$c=\frac{1}{2 \ln{\left(3 \right)}}$$$ en $$$f{\left(u \right)} = \sin{\left(u \right)}$$$:
$${\color{red}{\int{\frac{\sin{\left(u \right)}}{2 \ln{\left(3 \right)}} d u}}} = {\color{red}{\left(\frac{\int{\sin{\left(u \right)} d u}}{2 \ln{\left(3 \right)}}\right)}}$$
De integraal van de sinus is $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:
$$\frac{{\color{red}{\int{\sin{\left(u \right)} d u}}}}{2 \ln{\left(3 \right)}} = \frac{{\color{red}{\left(- \cos{\left(u \right)}\right)}}}{2 \ln{\left(3 \right)}}$$
We herinneren eraan dat $$$u=9^{x}$$$:
$$- \frac{\cos{\left({\color{red}{u}} \right)}}{2 \ln{\left(3 \right)}} = - \frac{\cos{\left({\color{red}{9^{x}}} \right)}}{2 \ln{\left(3 \right)}}$$
Dus,
$$\int{9^{x} \sin{\left(9^{x} \right)} d x} = - \frac{\cos{\left(9^{x} \right)}}{2 \ln{\left(3 \right)}}$$
Voeg de integratieconstante toe:
$$\int{9^{x} \sin{\left(9^{x} \right)} d x} = - \frac{\cos{\left(9^{x} \right)}}{2 \ln{\left(3 \right)}}+C$$
Antwoord
$$$\int 9^{x} \sin{\left(9^{x} \right)}\, dx = - \frac{\cos{\left(9^{x} \right)}}{2 \ln\left(3\right)} + C$$$A