$$$\frac{1}{x^{24}}$$$의 적분

$$$\int \frac{1}{x^{24}}\, dx$$$을(를) 구하시오.

멱법칙($$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$)을 $$$n=-24$$$에 적용합니다:

$${\color{red}{\int{\frac{1}{x^{24}} d x}}}={\color{red}{\int{x^{-24} d x}}}={\color{red}{\frac{x^{-24 + 1}}{-24 + 1}}}={\color{red}{\left(- \frac{x^{-23}}{23}\right)}}={\color{red}{\left(- \frac{1}{23 x^{23}}\right)}}$$

따라서,

$$\int{\frac{1}{x^{24}} d x} = - \frac{1}{23 x^{23}}$$

적분 상수를 추가하세요:

$$\int{\frac{1}{x^{24}} d x} = - \frac{1}{23 x^{23}}+C$$

$$$\int \frac{1}{x^{24}}\, dx = - \frac{1}{23 x^{23}} + C$$$A