$$$\frac{x^{5}}{15} - \frac{x^{3}}{3} + x$$$의 적분

$$$\int \left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)\, dx$$$을(를) 구하시오.

각 항별로 적분하십시오:

$${\color{red}{\int{\left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)d x}}} = {\color{red}{\left(\int{x d x} - \int{\frac{x^{3}}{3} d x} + \int{\frac{x^{5}}{15} d x}\right)}}$$

멱법칙($$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$)을 $$$n=1$$$에 적용합니다:

$$- \int{\frac{x^{3}}{3} d x} + \int{\frac{x^{5}}{15} d x} + {\color{red}{\int{x d x}}}=- \int{\frac{x^{3}}{3} d x} + \int{\frac{x^{5}}{15} d x} + {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=- \int{\frac{x^{3}}{3} d x} + \int{\frac{x^{5}}{15} d x} + {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$

상수배 법칙 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$을 $$$c=\frac{1}{3}$$$와 $$$f{\left(x \right)} = x^{3}$$$에 적용하세요:

$$\frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - {\color{red}{\int{\frac{x^{3}}{3} d x}}} = \frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - {\color{red}{\left(\frac{\int{x^{3} d x}}{3}\right)}}$$

멱법칙($$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$)을 $$$n=3$$$에 적용합니다:

$$\frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - \frac{{\color{red}{\int{x^{3} d x}}}}{3}=\frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - \frac{{\color{red}{\frac{x^{1 + 3}}{1 + 3}}}}{3}=\frac{x^{2}}{2} + \int{\frac{x^{5}}{15} d x} - \frac{{\color{red}{\left(\frac{x^{4}}{4}\right)}}}{3}$$

상수배 법칙 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$을 $$$c=\frac{1}{15}$$$와 $$$f{\left(x \right)} = x^{5}$$$에 적용하세요:

$$- \frac{x^{4}}{12} + \frac{x^{2}}{2} + {\color{red}{\int{\frac{x^{5}}{15} d x}}} = - \frac{x^{4}}{12} + \frac{x^{2}}{2} + {\color{red}{\left(\frac{\int{x^{5} d x}}{15}\right)}}$$

멱법칙($$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$)을 $$$n=5$$$에 적용합니다:

$$- \frac{x^{4}}{12} + \frac{x^{2}}{2} + \frac{{\color{red}{\int{x^{5} d x}}}}{15}=- \frac{x^{4}}{12} + \frac{x^{2}}{2} + \frac{{\color{red}{\frac{x^{1 + 5}}{1 + 5}}}}{15}=- \frac{x^{4}}{12} + \frac{x^{2}}{2} + \frac{{\color{red}{\left(\frac{x^{6}}{6}\right)}}}{15}$$

따라서,

$$\int{\left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)d x} = \frac{x^{6}}{90} - \frac{x^{4}}{12} + \frac{x^{2}}{2}$$

적분 상수를 추가하세요:

$$\int{\left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)d x} = \frac{x^{6}}{90} - \frac{x^{4}}{12} + \frac{x^{2}}{2}+C$$

$$$\int \left(\frac{x^{5}}{15} - \frac{x^{3}}{3} + x\right)\, dx = \left(\frac{x^{6}}{90} - \frac{x^{4}}{12} + \frac{x^{2}}{2}\right) + C$$$A