$$$2 x^{\frac{4}{3}}$$$의 적분

$$$\int 2 x^{\frac{4}{3}}\, dx$$$을(를) 구하시오.

상수배 법칙 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$을 $$$c=2$$$와 $$$f{\left(x \right)} = x^{\frac{4}{3}}$$$에 적용하세요:

$${\color{red}{\int{2 x^{\frac{4}{3}} d x}}} = {\color{red}{\left(2 \int{x^{\frac{4}{3}} d x}\right)}}$$

멱법칙($$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$)을 $$$n=\frac{4}{3}$$$에 적용합니다:

$$2 {\color{red}{\int{x^{\frac{4}{3}} d x}}}=2 {\color{red}{\frac{x^{1 + \frac{4}{3}}}{1 + \frac{4}{3}}}}=2 {\color{red}{\left(\frac{3 x^{\frac{7}{3}}}{7}\right)}}$$

따라서,

$$\int{2 x^{\frac{4}{3}} d x} = \frac{6 x^{\frac{7}{3}}}{7}$$

적분 상수를 추가하세요:

$$\int{2 x^{\frac{4}{3}} d x} = \frac{6 x^{\frac{7}{3}}}{7}+C$$

$$$\int 2 x^{\frac{4}{3}}\, dx = \frac{6 x^{\frac{7}{3}}}{7} + C$$$A