$$$\frac{\cos{\left(\theta \right)}}{1312}$$$의 적분

$$$\int \frac{\cos{\left(\theta \right)}}{1312}\, d\theta$$$을(를) 구하시오.

상수배 법칙 $$$\int c f{\left(\theta \right)}\, d\theta = c \int f{\left(\theta \right)}\, d\theta$$$을 $$$c=\frac{1}{1312}$$$와 $$$f{\left(\theta \right)} = \cos{\left(\theta \right)}$$$에 적용하세요:

$${\color{red}{\int{\frac{\cos{\left(\theta \right)}}{1312} d \theta}}} = {\color{red}{\left(\frac{\int{\cos{\left(\theta \right)} d \theta}}{1312}\right)}}$$

코사인의 적분은 $$$\int{\cos{\left(\theta \right)} d \theta} = \sin{\left(\theta \right)}$$$:

$$\frac{{\color{red}{\int{\cos{\left(\theta \right)} d \theta}}}}{1312} = \frac{{\color{red}{\sin{\left(\theta \right)}}}}{1312}$$

따라서,

$$\int{\frac{\cos{\left(\theta \right)}}{1312} d \theta} = \frac{\sin{\left(\theta \right)}}{1312}$$

적분 상수를 추가하세요:

$$\int{\frac{\cos{\left(\theta \right)}}{1312} d \theta} = \frac{\sin{\left(\theta \right)}}{1312}+C$$

$$$\int \frac{\cos{\left(\theta \right)}}{1312}\, d\theta = \frac{\sin{\left(\theta \right)}}{1312} + C$$$A